A body is projected upwards with a velocity u. It passes through a certain point above the ground after t1. The time after which the body passes through the same point during the return journey is

Suppose v be the velocity attained by the body after time t1.Then v=u−gt1 …..(i)Let the body reach the same point at time t2. Now velocity will be downwards with same magnitude v. Then−v=u−gt2 ......(ii) (i) −(ii)⇒2v=gt2−t1 or t2−t1=2vg=2gu−gt1=2ug−t1

A body is projected upwards with a velocity u. It passes through a certain point above the ground after t1. The time after which the body passes through the same point during the return journey is

Suppose v be the velocity attained by the body after time t1.Then v=u−gt1 …..(i)Let the body reach the same point at time t2. Now velocity will be downwards with same magnitude v. Then−v=u−gt2 ......(ii) (i) −(ii)⇒2v=gt2−t1 or t2−t1=2vg=2gu−gt1=2ug−t1

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A body is projected upwards with a velocity u. It passes through a certain point above the ground after t₁. The time after which the body passes through the same point during the return journey is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$(\frac{u}{g} - t_{1}^{2})$

$2 (\frac{u}{g} - t_{1})$

$3 (\frac{u^{2}}{g} - t_{1})$

$3 (\frac{u^{2}}{g^{2}} - t_{1})$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Suppose v be the velocity attained by the body after time t₁.

Then $v = u - g t_{1}$ …..(i)

Let the body reach the same point at time t₂. Now velocity will be downwards with same magnitude v. Then

$\begin{array}{l} - v = u - g t_{2} . . . . . . (i i) \\ (i) - (ii) \Rightarrow 2 v = g (t_{2} - t_{1}) \\ or t_{2} - t_{1} = \frac{2 v}{g} = \frac{2}{g} (u - g t_{1}) = 2 (\frac{u}{g} - t_{1}) \end{array}$