A body is projected vertically from the surface of Earth with kinetic energy K₁ and when it comes
to momentary rest, it is given a horizontal velocity so that its kinetic energy is K₂ and it goes into
circular orbit. Then

For escape from surface kinetic energy required is ${\mathrm{K}}_1+2{\mathrm{K}}_2$

The altitude of the orbit is $\left(\frac{{\mathrm{K}}_1}{2{\mathrm{K}}_2}\right)$ times radius of earth

If initially, the body had been projected horizontally with a kinetic energy of  $\frac{{\mathrm{K}}_1}{2}+{\mathrm{K}}_1$ it would
have gone into circular orbit. 

${\mathrm{K}}_1>{\mathrm{K}}_2$