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A body is projected vertically up with certain velocity. The ratio of velocity of projection to velocity at a point in its path is 3 : 4. The ratio of potential to kinetic energies at that point is

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3 : 25

1 : 25

3 : 28

1 : 20

answer is A.

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Detailed Solution

$\frac{h}{H - h} = \frac{3}{4} \Rightarrow H = \frac{7}{3} h$

When velocity of projection is doubled, Maximum Height is quadrupled

$H^{1} = 4 H = \frac{28}{3} h$

$\frac{P E}{K E} = \frac{h}{H' - h} = \frac{3}{25}$

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