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Q.

A body is projected vertically upwards. If t1 and t2 be the times at which it is at height h above the point of projection while ascending and descending respectively, then h is

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a

12 gt1t2

b

4 gt1t2

c

gt1t2

d

2gt1t2

answer is A.

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Detailed Solution

O to A: 

h=u1-12gt12 ----(i)

O to B :

h=ut2-12gt2 -----(ii)

Solving u=g2t1+t2

h=12gt1t2

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