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Q.

A body is projected vertically upwards with a velocity 'U'. It crosses a point in its journey at a height 'h' twice, just after 1 and 7 seconds. The value of U in ms^-1 is $[g = 10 {ms}^{- 2}]$

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a

50

b

40

c

20

d

30

answer is B.

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Detailed Solution

$t_{1} + t_{2} = T = \frac{2 u}{g}$

$1 + 7 = \frac{2 u}{g} u = 40$

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A body is projected vertically upwards with a velocity 'U'. It crosses a point in its journey at a height 'h' twice, just after 1 and 7 seconds. The value of U in ms-1 is [g=10ms-2]