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A body is projected with a velocity 60 ms^-1 at 30^o to horizontal. Its initial velocity vector is

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$10 \hat{i} + 10 \sqrt{3} \hat{j}$

$30 \hat{i} + 30 \sqrt{3} \hat{j}$

$30 \sqrt{3} \hat{i} + 30 \hat{j}$

$30 \sqrt{3} \hat{i}$

answer is C.

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Detailed Solution

$\begin{array}{l} \bar{u} = ucos θ \hat{i} + usin θ \hat{j} = 60 \cos 30^{o} \hat{i} + 60 \sin 30^{o} \hat{j} \\ = 30 \sqrt{3} \hat{i} + 30 \hat{j} \end{array}$

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