A body is projected with a velocity $60\text{m/s}$ at an angle $\text{30°}$ with horizontal. It’s displacement after 2sec is(in metres)

$\text{y}={\left(\text{u}\sin \theta \right)}^2\text{t}-\frac{1}{2}{\text{gt}}^{\text{2}}$

$=\left(60\times \frac{1}{2}\right).2-\frac{1}{2}\times 10\times 4$

$=60-20$

$=40\text{m}$                                                

$x=\left(\text{u}\cos \theta \right)\text{t}$

$=\text{60}\times \frac{\sqrt{3}}{2}\times 2$

$=60\sqrt{3}\text{m}$

$\overline{s}=x\hat{i}+y\hat{j}$

$=60\sqrt{3}\hat{i}+40\hat{j}$