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Q.

A body is projected with a velocity ‘u’ making an angle $θ$ with horizontal. The time after which its vertical component of velocity is equal to horizontal component is

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a

\frac{u}{g \cos θ}

b

\frac{u}{g} (\sin θ - \cos θ)

c

\frac{u}{g} (\cos θ - \sin θ)

d

\frac{u}{g \sin θ}

answer is C.

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Detailed Solution

u sin θ - gt = u \cos θ

$gt = u (\sin θ - \cos θ)$

$t = \frac{u}{g} (\sin θ - \cos θ)$

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