A body is projected with certain initial velocity, certain angle from the ground, the speed of projectile at it’s maximum height is 23 times the speed at half of the maximum height. Then find the angle of projection (in degree) from the horizontal ground.

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A body is projected with certain initial velocity, certain angle from the ground, the speed of projectile at it’s maximum height is $\sqrt{\frac{2}{3}}$ times the speed at half of the maximum height. Then find the angle of projection (in degree) from the horizontal ground.

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answer is 45.

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(45)
Sol. $u_{x} = u \cos θ$

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