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A body is projected with velocity $24 {ms}^{- 1}$ making an angle $30 °$ with the horizontal. The vertical component of its velocity after 2s is $(g = 10 {ms}^{- 1})$

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8 {ms}^{- 1}

down ward

32 {ms}^{- 1}

upward

32 {ms}^{- 1}

down ward

8 {ms}^{- 1}

upward

answer is B.

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Detailed Solution

u = 24 {ms}^{- 1} θ = 30 °

After $t = 2 s$

Vertical component of velocity

$V = usin θ - g (2) = 2 u \sin 30 ° - 2 g$

$= 24 \times \frac{1}{2} - 10 \times 2$

$= 12 - 20$

$= - 8 {ms}^{- 1} = 8 {ms}^{- 1} downwards$

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