A body is released from a great height falls freely towards the earth. Another body is released from the same height exactly a second later. Then, the separation between two bodies, 2s after the release of the second body is, nearly:

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25m

30m

20m

15m

answer is C.

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Detailed Solution

$As, S = ut + \frac{1}{2} {at}^{2}$
For 1st body, u=0 and a=g (freely falling body)
Distance covered in 3 s, $S_{1} = 0 + \frac{1}{2} g (3)^{2}$
For 2nd body
Distance covered in 2s, $S_{2} = 0 + \frac{1}{2} g (2)^{2}$
$∴ S_{1} - S_{2} = \frac{1}{2} g [(3)^{2} - (2)^{2}] = \frac{1}{2} g [9 - 4] = 25 m$

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