Q.

A body is sliding down an inclined plane having coefficient of friction 1/3 . If the normal reaction is three times that of the resultant downward force along the incline, the angle between the inclined plane and the horizontal is

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a

tan1(2)

b

tan1(12)

c

tan1(32)

d

tan1(23)

answer is C.

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Detailed Solution

mgcosθ=3(mgsinθμmgcosθ)

cosθ=3sinθcosθ3×3

cosθ+cosθ=3sinθ

2cosθ=3sinθ

tanθ=23

θ=tan1(2/3)

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