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A body is thrown horizontally from the top of a tower of 5m height. It touches the ground at a distance of 10m from the foot of the tower. Then initial velocity of the body is (g = 10ms^-2)

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10 ms^-1

5 ms^-1

20 ms^-1

2.5 ms^-1

answer is C.

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Detailed Solution

$\begin{array}{l} R = u \sqrt{\frac{2 h}{g}} \\ 10 = u \sqrt{\frac{2 \times 5}{10}} \end{array}$
$u = 10 {ms}^{- 1}$

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