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A body is thrown vertically up with certain initial velocity, the potential and kinetic energies of the body are equal at a point P in its path. If the same body is thrown with double the velocity upwards, the ratio of potential and kinetic energies of the body when it crosses the same point is

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1 : 8

1 : 7

1 : 3

1 : 1

answer is C.

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Detailed Solution

TE at point of projection $\frac{1}{2} m v^{2} = 2 u n i t s$

TE on the ground $= \frac{1}{2} M (2 v)^{2} = 8 units$

$h \to remains same ∴ P E : K E = 1 : 7$

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