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A body is thrown vertically upward from a point on ground. The body reaches a height above the ground at times t = 3 sec and t = 6 sec. Then velocity of projection is

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20 m/s

40 m/s

45 m/s

30 m/s

answer is C.

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Detailed Solution

v=u+at

The velocities at t=3m/s and t=6 m/s will be equal and opposite.

hence u-3g= 6g-u

9g= 2u

u= 45m/s

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