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Q.

A body is thrown with velocity (4i + 3j ) metre per second. Its maximum height is (g = 10 ms^–2)

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a

0.8 m

b

0.9 m

c

2.5 m

d

0.45 m

answer is D.

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Detailed Solution

$\vec{u} = (4 \hat{i} + 3 \hat{j}) m / s$

$usinθ = 3 m / s$

$H_{max} = \frac{u^{2} \sin^{2} θ}{2 g} = \frac{(3)^{2}}{2 \times 10} = 0.45 m$

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