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Q.

A body moves a distance of 20m along a straight line under the action of a force of 10N. If the work done is 100J, the angle between force and displacement vectors is,

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a

0⁰

b

30⁰

c

60⁰

d

45⁰

answer is D.

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Detailed Solution

W = FScos $θ$

100 = 10 x 20 x cos $θ$ ⇒ $θ$ = 60⁰

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