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A body moves along a circular path of radius 5m. The coefficient of friction between the surface of the path and body is 0.5. The angular velocity is radian s^–1 with which the body should move so that it does not leave
the path is (g=10ms^–2)

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answer is D.

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Detailed Solution

The frictional force will be the centripetal acceleration.

$μg = {rω}^{2} \Rightarrow ω = \sqrt{\frac{μg}{r}} = \sqrt{\frac{0.5 g}{5}} = 1$

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