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Q.

A body of mass 400 g slides on a rough horizontal surface. If the frictional force is 3 N, then the magnitude of contact force is $(g = 10 {ms}^{- 2})$

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a

4 N

b

5 N

c

3 N

d

7 N

answer is D.

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Detailed Solution

Question Image

$f = 3N$

$R = ?$

$N = mg = 0 .4 \times 10$

$N = 4N$

$\sqrt{N^{2} + f^{2}}$

$= \sqrt{4^{2} + 3^{2}}$

$= \sqrt{25}$

$R = 5 N$

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