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A body of density D₁ and mass M is moving downward in glycerine of density D₂ . What is the viscous force acting on it?

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$Mg D_{1}$

$Mg (1 - \frac{D_{1}}{D_{2}})$

$Mg (1 - \frac{D_{2}}{D_{1}})$

$Mg D_{2}$

answer is A.

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Detailed Solution

Assuming the body has attained terminal velocity, from force balance F_Weight - F_Buoyancy - F_Viscosity = 0.

Hence F_Buoyancy = F_Weight - F_Viscosity = $M g - (\frac{M}{D_{1}}) D_{2} g = M g (1 - \frac{D_{2}}{D_{1}})$

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