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A body of mass 0.01 kg executes simple harmonic motion about x=0 under the influence of a force shown below. The amplitude of velocity of the body in S.H.M. is

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2 ms^-1

40 ms^-1

20 ms^-1

10 ms^-1

answer is B.

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Detailed Solution

$F = {mω}^{2} A$
$\begin{array}{l} 8 = 10^{- 2} ω^{2} \times 2 \\ ω = \sqrt{400} = 20 {rad s}^{- 1} \end{array}$
$V_{\max} = Aω = 2 \times 20 {ms}^{-1}$

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