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A body of mass 0.5 kg is moving at a constant velocity of $2 {ms}^{- 1}$ . To bring it to rest in 2 metres, the work done is

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0.5 J

2.0 J

1.0 J

4.0 J

answer is B.

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Detailed Solution

M = 0.5 kg, S = 2m
$u = 2 m / s$
We know that work done = change in K.E
$ΔK . E = \frac{1}{2} {mv}^{2} - 0$
$= \frac{1}{2} (0.5) {(2)}^{2} = 1 J$

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