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A body of mass 0.5 kg is projected vertically upwards with velocity of 40 m/s. Its maximum gravitational potential energy is found to be 80% of initial kinetic energy. Then the average air resistance acting on the body is

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2.50 N

1.25 N

4.25 N

1.5 N

answer is B.

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Detailed Solution

$\begin{array}{l} m g H = \frac{80}{100} \times \frac{1}{2} m V^{2} \\ \Rightarrow H = \frac{2 V^{2}}{5 g} = \frac{2 \times 40^{2}}{5 \times 10} m = 64 m \end{array}$

At the highest lost energy = 20% of initial K.E

$\begin{array}{l} ∴ R \times 64 = \frac{20}{100} \times \frac{1}{2} \times 0.5 \times 40^{2} \\ \Rightarrow R = 1.25 N \end{array}$

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