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Q.

A body of mass 0.5 kg,  travels on straight line path with velocity v=3x2+4 m/s. Then the net work done by the force during its displacement from x = 0 to x = 2m in …………… J.

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answer is 60.

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Detailed Solution

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v=3x2+4

at x=0, x=2

v1=4, v2=12+4=16

Work done = Δ kinetic energy

=12m(v22−v12)=60J

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