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A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction?

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20 J

19.5 J

21 J

18 J

answer is A.

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Detailed Solution

Concept- We shall look for kinetic energy first, followed by potential energy. By simply calculating the difference between the two, we may determine the energy lost due to air friction.
Initial velocity

u = 20 m s, m = 1 kg

Kinetic energy = maximum potential energy
Initial kinetic energy

= 12 × 1 × 202 = 200 J

Applying the law of conservation of energy,

Mgh (max) = 200 J

∴ h = 20 m

The height traveled by the body,
h’= 18 m
Loss of energy due to air friction

= mgh - mg

h’
Energy lost =

200 J - 1 \times 10 \times 18 J

=20 J
Hence, the correct option is 1.

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