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A body of mass 10 kg is moving along a straight line with a linear momentum of 240 kg $m s^{- 1}$ . If a constant force of 20 N acts for 5s opposite to direction of motion, the work done by the force during this time is

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1900 J

1440 J

1190 J

1200 J

answer is A.

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Detailed Solution

$F \times Δ t = P_{f} - P_{i}$

$- 20 \times 5 = P_{f} - 240 \Rightarrow P_{f} = 140$

$w = \frac{1}{2 m} (P_{f}^{2} - P_{i}^{2}) = \frac{1}{2 \times 10} [{(140)}^{2} - {(240)}^{2}]$

$w = 1900 J$

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