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A body of mass 10 kg is moving with an initial speed of 20 m/s. The body stops after 5s due to friction between body and the floor. The value of the coefficient of friction is. (take acceleration due to gravity g= 10 ms ^-2)

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0.3

0.2

0.5

0.4

answer is B.

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Detailed Solution

$\begin{array}{l} m = 10 kg, u = 20 m / s, v = 0, t = 5 \sec \\ a = \frac{- f_{k}}{m} = \frac{- μmg}{m} \Rightarrow a = - μg \\ v = u + at \\ 0 = 20 - μg (t) \Rightarrow 20 = μ (10) (5) \\ μ = \frac{2}{5} = 0.4 \end{array}$

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