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A body of mass 10 kg lies on a rough inclined plane of inclination $θ = \sin^{- 1} \frac{3}{5}$ with the horizontal. When a force of 30 N is applied on the block parallel to and upward the plane, the total reaction by the plane on the block is nearly along:

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answer is A.

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Detailed Solution

Frictional force along the in upward direction = $10 g \sin θ - 30 = 30 N$

N = mg $\cos θ = 80 N$

Direction of R is along OA.

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