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A body of mass 10 mg is moving with a velocity of 100 m/sec. the de-Broglie wave length associated with it would be $(h = 6.63 \times 10^{- 34} J / s)$

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$6.63 \times 10^{- 34} m$

$6.63 \times 10^{- 35} m$

$6.63 \times 10^{- 31} m$

$6.63 \times 10^{- 37} m$

answer is C.

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Detailed Solution

$λ = \frac{h}{m \times v}$ $= 6.63 \times 10^{- 31}$

$m = 10 m g (o r) 10 \times 10^{- 6} k g$

$v = 100 m / \sec$

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