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Q.

A body of mass 10kg lies on a rough inclined plane of inclination $θ = \sin^{- 1} (\frac{3}{5})$ with the horizontal. When the force of $30 N$ is applied on the block parallel to and upward the plane, the total force by the plane on the block is nearly along

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a

O A

b

O C

c

O D

d

O B

answer is A.

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Detailed Solution

$m g \sin θ = (10) (10) (3 / 5) = 60 N$

This $60 N > 30 N$ . Therefore, friction force f will act in upward direction.

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F= $\sqrt{N^{2} + f^{2}}$ = net force by plane on the block.

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A body of mass 10kg lies on a rough inclined plane of inclination θ=sin-135 with the horizontal. When the force of 30 N is applied on the block parallel to and upward the plane, the total force by the plane on the block is nearly along