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Q.

A body of mass 10kg lies on a rough inclined plane of inclination θ=sin-135 with the horizontal. When the force of 30 N is applied on the block parallel to and upward the plane, the total force by the plane on the block is nearly along

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a

O A

b

O C

c

O D

d

O B

answer is A.

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Detailed Solution

 mgsinθ=(10)(10)(3/5)=60 N

This 60 N>30 N. Therefore, friction force f will act in upward direction.

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F=N2+f2= net force by plane on the block.

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