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Q.

A body of mass 10kg slides along a rough horizontal surface. The coefficient of friction is 1/3 Taking g=10m/s2, the least force which acts at an angle of 300 to the horizontal is ___N.

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answer is 50.

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Detailed Solution

Let P fore is acting at an angel 300 with the horizontal. For the condition of motion F = μR
  P cos300 = μ(mg – P sin300)
⇒P32=13(100−P12)⇒3P2=(100−P2)
⇒2P=100⇒P=50N

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