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Q.

A body of mass 1kg is moving with critical velocities in a vertical circular path of radius 1m. The difference between the kinetic energies at the highest and lowest position is g=10m/s2

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a

45J

b

10 J

c

20 J

d

10(51)J

answer is A.

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Detailed Solution

Difference in kinetic energy =1/2m[(5gr)2(gr)2]

=2mgr=2×1×10×1=20J

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