A body of mass 1kg is moving with velocity 30 ms^-1due north. It is acted on by a force of 10N due east for 4 seconds. Find the velocity of the body after the force ceases to act

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$30 \sqrt{2} m / s$

40 m/s

50 m/s

45 m/s

answer is C.

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Detailed Solution

$\vec{v_{y}} = \vec{u} = 30 \hat{j} m / s$

$\begin{array}{r} \vec{V_{x}} = (\frac{10}{1}) \times 4 \hat{i} m / s = 40 \hat{i} m / s \\ ∴ V = \sqrt{V_{x}^{2} + V_{y}^{2}} = 50 m / s . \end{array}$

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