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Q.

A body of mass 1kg is thrown upwards with a velocity of 20 m/s. It momentarily comes to rest after attaining a height of 18m. How much energy is lost due to air friction? (g = 10 m/s2)

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a

40 J

b

10 J

c

20 J

d

30 J

answer is B.

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Detailed Solution

By using Work-Energy Theorem
W=ΔKE
−mgh+Wfriction =0−12mu2
Loss in energy = =12mu2−mgh
=12(1)(20)2−(1×10×18)=20J

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