A body of mass 1kg is thrown upwards with a velocity of 20 m/s. It momentarily comes to rest after attaining a height of 18m. How much energy is lost due to air friction? (g = 10 m/s²)

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40 J

10 J

20 J

30 J

answer is B.

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Detailed Solution

By using Work-Energy Theorem
$W = ΔKE$
$- mgh + W_{friction} = 0 - \frac{1}{2} {mu}^{2}$
Loss in energy = $= \frac{1}{2} {mu}^{2} - mgh$
$= \frac{1}{2} (1) (20)^{2} - (1 \times 10 \times 18) = 20 J$

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