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A body of mass 1kg moves along x-axis such that it’s velocity varies with x co-ordinate according to the relation $v = 10 x^{2}$ , then find net force (in N) on body at x = 10 cm.

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Detailed Solution

$a = v \frac{d v}{d x} a = (10 x^{2}) (20 x) = 200 x^{3} = 200 \times \frac{1}{10} \times \frac{1}{10} \times \frac{1}{10} = 0.2 F = m a F = 1 \times a F = 0.2 N$

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