A body of mass 1kg travels on straight line path with velocity $v = (3 x^{2} + 4) m / s .$ The net work done by the force during its displacement from $x = 0 t o x = 2 m$ is:

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60J

120J

128J

64J

answer is C.

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Detailed Solution

by work-energy theorem $W = Δ K \Rightarrow W = \frac{1}{2} m (v_{f}^{2} - v_{i}^{2}) \Rightarrow W = \frac{1}{2} \times 1 \times (16^{2} - 4^{2}) \Rightarrow W = \frac{1}{2} \times 240 \Rightarrow W = 120 J$

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