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Q.

A body of mass 2 kg is allowed to slide down along a quadrant of a circle from the horizontal position. In reaching to the bottom, Its velocity is 6m/sec. The work done in overcoming the friction is 10J. The radius of circle is (g = 10ms–2)

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a

1.5m

b

2m

c

2.3m

d

4m

answer is D.

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Detailed Solution

By using conservation of energy,

mgh=12×mv210

2×10×h=12×2×62+10

20h=36+10

h=2.3

Hence the correct answer is 2.3m.

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