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A body of mass 2 kg is moving towards east with a uniform speed of 2 ${ms}^{- 1}$ . A force of 3 N is applied to it towards north. The magnitude of the displacement of the body 2 s after the applications of force is

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4 m

5 m

6 m

7 m

answer is B.

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Detailed Solution

m = 2 kg

$\vec{v} = 2 \hat{i} m / s$

$\vec{F} = 3 \hat{j} N$

$\vec{a} = \frac{\vec{F}}{m} = \frac{3}{2} \hat{j} m / s^{2}$

Since $\vec{s} = \vec{v t} + \frac{1}{2} \vec{a} t^{2}$

$\vec{s} = (2 \hat{i}) 2 + \frac{1}{2} (\frac{3}{2}) (4) \hat{j}$

$\vec{s} = 4 \hat{i} + 3 \hat{j}$

$|\vec{s}| = \sqrt{4^{2} + 3^{2}} = 5 m$

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