A body of mass 2 kg is moving up a smooth inclined plane, rising 1 in 30, with velocity 60 m/s. If efficiency is 40%, the power required is

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20 W

60 W

100 W

40 W

answer is D.

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Detailed Solution

$F = m g \sin θ = \frac{2}{3} N$

$\begin{array}{l} P_{out put} = Fv = \frac{2}{3} \times 60 = 40 W \\ n = \frac{outout power}{Input power} \\ \frac{40}{100} = \frac{40 W}{Input power} \\ Input power = 100 W \end{array}$

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