Q.

A body of mass 2 kg is moving with a constant acceleration of (2i^+3j^k^)ms2. If the displacement made by the body is (3^i^j^+2k^)m n then the work done is

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a

2 J

b

10 J

c

22 J

d

12 J

answer is B.

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Detailed Solution

The work done is given by W=F.s=ma.s=2(2i^+3j^k^).(3^i^j^+2k^)=26-3-2=2 J

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