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A body of mass 2 kg is placed on a horizontal surface having coefficients of kinetic friction 0.4 and static friction 0.5. If the force applied on the body is 2.5 N, then the frictional force acting on the body will be (g =10 ms^-2)

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10N

20N

2.5N

answer is D.

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Detailed Solution

Limiting friction= 0.5 x 2 x 10 = 10N

The applied force is less than force of friction, therefore the force of friction is equal to the applied force.

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