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Q.

A body of mass 2 kg is projected with a velocity of 40 m/s at an angle  60°with the ground. The K.E of the body at the highest point reached is

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a

Zero

b

200 J

c

300 J

d

400 J

answer is D.

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Detailed Solution

Hint: m=2kg, u=40 ms1,   θ=60°

K.E=?

K.E=12muf2

K.E=12×2×u2cos260

K.E=400 J

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