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A body of mass $2 kg$ is thrown up with a speed of $25 m / s$ . Find its maximum potential energy.

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0 J

125 J

25 J

625 J

answer is D.

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Detailed Solution

A body of mass

2 kg

is thrown up with a speed of

25 m / s

. Its maximum potential energy will be

625 J

.
Mass,

m = 2 kg

Initial velocity,

u = 25 m / s

Final velocity,

v = 0 m / s

g = - 9.8 m {/ s}^{2}

As per energy conservation law, All the kinetic energy will be converted into potential energy at the highest point. So,
Maximum potential energy

=

Initial kinetic energy

\Rightarrow = \frac{1}{2} m v^{2}

\Rightarrow = 0.5 \times 2 kg \times 2 5^{2} m / s

\Rightarrow = 625 J

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