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A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/sec comes to rest after 2 sec. If one wants to keep this body moving on the same surface with a velocity of 4 m/sec, the force required is

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a

8 N

b

4 N

c

Zero

d

2 N

answer is B.

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Detailed Solution

$\begin{array}{l} u = 4 m / s, v = 0, t = 2 \sec \\ v = u + at \Rightarrow 0 = 4 + 2 a \Rightarrow a = - 2 m / s^{2} \end{array}$
$∴$ Retarding force $= ma = 2 \times 2 = 4$ N
This force opposes the motion. If the same amount of force is applied in forward direction, then the body will move with constant velocity.

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A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/sec comes to rest after 2 sec. If one wants to keep this body moving on the same surface with a velocity of 4 m/sec, the force required is