A body of mass 2 kg moving with a velocity (2i^+j^+k^)ms−1 then its momentum in kg ms−1 is

p¯=mv¯ =2(2i+j+k) p¯=4i^+2j^+2k^

p¯=mv¯ =2(2i+j+k) p¯=4i^+2j^+2k^

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A body of mass 2 kg moving with a velocity $(2 \hat{i} + \hat{j} + \hat{k}) {ms}^{- 1}$ then its momentum in $kg {ms}^{- 1}$ is

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4 \hat{i} + 2 \hat{j} + 2 \hat{k}

2 \hat{i} + 4 \hat{j} + 2 \hat{k}

4 \hat{i} - 2 \hat{j} + 2 \hat{k}

2 \hat{i} + 2 \hat{j} + 4 \hat{k}

answer is B.

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\bar{p} = m \bar{v}

$= 2 (2 i + j + k)$

$\bar{p} = 4 \hat{i} + 2 \hat{j} + 2 \hat{k}$

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