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A body of mass 2 kg rests on a rough inclined plane making an angle 30° with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is:

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$9.8 \times \sqrt{3} N$

9.8 N

0.7 x 9.8 N

$0 .7 \times 9 .8 \times \sqrt{3} N$

answer is A.

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Detailed Solution

If the body is at rest, friction = applied force and not $μ$ R

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