A body of mass 20 Kg moves with an acceleration of 2 m/s2. The rate of change of momentum in S.I. unit is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

answer is A.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

We can say that Newton's second law of motion , force is the defined as the rate of change of momentum. Thus, we get

F = \frac{∆ p}{∆ t}

. Here, p is the momentum and t is the time.
Also, if body has a constant mass then

F = m \times a

where, m is the mass and a is the acceleration.
By equating both the equations of force we get

\frac{∆ p}{∆ t} = m \times a

But m = 20 Kg and a = 2 m/s2
So,

\frac{∆ p}{∆ t} = 20 \times 2

\frac{∆ p}{∆ t} = 40

N
Therefore, a body of mass 20 Kg moves with an acceleration of 2 m/s2 . The arte of change of momentum in S.I. unit is 40 N.

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test