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A body of mass 200 g requires 252 J for $10 ° C$ rise of temperature, its thermal capacity is

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126 {JK}^{- 1}

504 {JK}^{- 1}

0.126 {JK}^{- 1}

25.2 {JK}^{- 1}

answer is D.

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Detailed Solution

m = 200 g,Q = 252 J,t = 1 0°C

$\frac{Q}{t} = \frac{252}{10} = 25.2 5/c$

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