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A body of mass $200 g$ requires $252J$ for $10 ° C$ rise of temperature, its thermal capacity is

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0 {.126JK}^{- 1}

{504JK}^{- 1}

25 {.2JK}^{- 1}

{126JK}^{- 1}

answer is D.

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Detailed Solution

m = 200 g = 200 \times 1 0^{- 3} kg

$Q = 252J, Δ t = 10 ° C, H = ?$

Thermal capacity $= \frac{Q}{t} = \frac{252}{10}$

$= 25 . {2 JK}^{- 1}$

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