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A body of mass 2kg lying on ice which given a velocity of ${6ms}^{- 1}$ is stopped by friction is 5sec find the co-efficient of friction between block and ice $(g = 10 {ms}^{- 2})$

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Detailed Solution

Mass of body $m = 2 kg$

Velocity u= ${6ms}^{- 1}$

Time t=5sec

Acceleration $a = μ g$

From equation of motion

$v - u = a t$

$\Rightarrow v = u - μ_{k} g t$

$\Rightarrow 0 = 6 - μ_{k} \times 10 \times 5 \Rightarrow μ_{k} = \frac{6}{50}$

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